LOL Feel free to call me Baha, I don't mind. A lot of people call me that as well.
Okay so since they are linear equations, you already know it is y = mx + b, where b is the point at which the line crosses the y axis.
so for the first question, you are given: m (-2), x (-4), and y (5) so you just plug it in and solve for B
5 = -2(-4) + b (plug it in)
5 = 8 + b (multiply -2 and -4)
5 - 8 = b (move 8 over to the other side, don't forget that it changes sign to -8)
-3 = b
So therefore this equation is: y = -2x - 3
Do the same procedure for the next two!
For the 2nd set of equations... You know TWO y values and TWO x values. You solve for m (slope) which is (y2-y1)/(x2-x1). Then, you solve for b by using the method I taught you above.
So for the first one is:
m = (3 - (-1)/(0-4)
m = (3+1)/(-4)
m = 4/-4
m = -1
SO now you have y = -1x + b
Plug in ANY of the points given to you, either (4,-1) or (0,3) and solve for b.
Use BOTH points given to check your answer.
Using (4,-1)
-1 = -1(4) + b
-1 = -4 + b
-1 + 4 = b
3 = b
Therefore: y = -1x + 3
Using (0,3)
3 = -1(0) + b
3 = 0 + b
3 = b
Therefore: y = -1x + 3
Follow this example to solve for the rest of your homework :)
@Diablo: I studied math until 2nd year university? I learned this stuff a long time ago, haha. My "A" game is solving for numerous variables in quadratic functions.