LOL Feel free to call me Baha, I don't mind. A lot of people call me that as well.
Okay so since they are linear equations, you already know it is y = mx + b, where b is the point at which the line crosses the y axis.
so for the first question, you are given: m (2), x (4), and y (5) so you just plug it in and solve for B
5 = 2(4) + b (plug it in)
5 = 8 + b (multiply 2 and 4)
5  8 = b (move 8 over to the other side, don't forget that it changes sign to 8)
3 = b
So therefore this equation is: y = 2x  3
Do the same procedure for the next two!
For the 2nd set of equations... You know TWO y values and TWO x values. You solve for m (slope) which is (y2y1)/(x2x1). Then, you solve for b by using the method I taught you above.
So for the first one is:
m = (3  (1)/(04)
m = (3+1)/(4)
m = 4/4
m = 1
SO now you have y = 1x + b
Plug in ANY of the points given to you, either (4,1) or (0,3) and solve for b.
Use BOTH points given to check your answer.
Using (4,1)
1 = 1(4) + b
1 = 4 + b
1 + 4 = b
3 = b
Therefore: y = 1x + 3
Using (0,3)
3 = 1(0) + b
3 = 0 + b
3 = b
Therefore: y = 1x + 3
Follow this example to solve for the rest of your homework :)
